2N3904BU
Part Number: 2N3904BU
Manufacturer: onsemi / Fairchild
Description: Bipolar Transistors – BJT NPN Transistor General Purpose
Shipped from: Shenzhen/HK Warehouse
Stock Available: Check with us
ICRFQ.com - Electronic Components Distributor in China Since 2003
Part Number: 2N3904BU
Manufacturer: onsemi / Fairchild
Description: Bipolar Transistors – BJT NPN Transistor General Purpose
Shipped from: Shenzhen/HK Warehouse
Stock Available: Check with us
The 2N3904BU is a transistor, which is a type of semiconductor device that can switch or amplify electrical signals. Transistors may be found in almost all modern electronic devices. The base, the Collector, and the emitter are the three primary components that constitute a transistor. The voltage that controls whether or not current travels from the Collector to the emitter is applied at the base of the transistor. It can be used as either an amplifier or a switching device while current flows from the Collector to the emitter. Keep reading if you want to find out more about this device.
Because the 2N3904 is an NPN transistor, its Collector and emitter will remain open (in a state known as reverse bias) when the base pin is connected to the ground. However, when a signal is applied to the base pin, it will close (in a state known as forwarding bias). The gain value of the 2N3904 transistor is 300, which controls the amplification capacity of the transistor.
This transistor cannot be used to connect loads that require more than 200 milliamperes of current because the maximum amount of current that could travel via the Collector pin is just 200 milliamperes. To bias a transistor, we need to supply current to the base pin, and the current amount should not exceed 5 milliamperes (mA).
When this transistor is fully biased, it can let a current of up to 200 mA travel between the Collector and the emitter. This stage is referred to as the Saturation Region. The voltage allowed to be applied across the Collector-Emitter (VCE) or Collector-Base (VCB) could be 40V or 60V, respectively. When the base current is eliminated, the transistor turns off completely. This stage is referred to as the Cut-off Region, and the Base Emitter voltage can be close to 600 mV at this point.
As mentioned earlier, the Saturation and Cut-Off Region is where a transistor is operated when it serves its purpose as a switch. As was previously mentioned, a transistor will behave as a switch that is open when subjected to forward bias, and it will act as a switch that is closed when subjected to reverse bias. This biasing can be performed by applying the necessary current to the base pin. As was previously stated, the biasing current should not exceed 5 mA. Because the transistor will be destroyed by currents greater than 5 milliamperes, a resistor is always supplied in series with the base pin. The value of this resistor, denoted by RB, can be determined by utilizing the formulas provided below.
RB = VBE / IB
The value of VBE ought to be 5V for 2N3904, and the Base current (IB is dependent on the current flowing through the Collector) (IC). It is essential to keep the value of IB below mA.
When it is operating in its Active Region, a Transistor performs the function of an Amplifier. In various designs, it can amplify power, voltage, and current.
The following is a list of some of the configurations that can be found in amplifier circuits:
The most frequent and widespread setup is the common emitter type, which may be seen in the examples given above. Calculating the DC gain of the transistor when it is being used in an amplifier may be done with the help of the following formulas.
DC Current Gain is Calculated by Comparing the Collector Current (IC) to the Base Current (IB)
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